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-3x^2-6x+360=0
a = -3; b = -6; c = +360;
Δ = b2-4ac
Δ = -62-4·(-3)·360
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-66}{2*-3}=\frac{-60}{-6} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+66}{2*-3}=\frac{72}{-6} =-12 $
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